2x^2+10x+8/2X+2

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Solution for 2x^2+10x+8/2X+2 equation:


x in (-oo:+oo)

(8/2)*X+2*x^2+10*x+2 = 0

4*X+2*x^2+10*x+2 = 0

DELTA = 10^2-(2*4*(4*X+2))

DELTA = 100-8*(4*X+2)

100-8*(4*X+2) = 0

100-8*(4*X+2) = 0

84-32*X = 0

84-32*X = 0

84-32*X = 0 // - 84

-32*X = -84 // : -32

X = -84/(-32)

X = 21/8

DELTA = 0 <=> t_1 = 21/8

x = -10/(2*2) i X = 21/8

x = -5/2 i X = 21/8

( x = ((100-8*(4*X+2))^(1/2)-10)/(2*2) or x = (-(100-8*(4*X+2))^(1/2)-10)/(2*2) ) i X > 21/8

( x = ((100-8*(4*X+2))^(1/2)-10)/4 or x = (-((100-8*(4*X+2))^(1/2)+10))/4 ) i X > 21/8

X-21/8 > 0

X-21/8 > 0 // + 21/8

X > 21/8

x in { -5/2, ((100-8*(4*X+2))^(1/2)-10)/4, (-((100-8*(4*X+2))^(1/2)+10))/4 }

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